第二十八课--Microduino 8*8点阵横向移动显示/zh

Language	English

目的 本教程将在上一静态显示教程基础上横向移动笑脸动态显示。 设备 Microduino-Core Microduino-FT232R 其他硬件设备 面包板跳线 一盒 面包板 一块 8*8点阵LED 一个 74HC595 2个 USB数据连接线 一根 8*8点阵LED的型号是：LD-1088BS，其引脚定义如下图： 原理图 引脚表： 点阵ROW 点阵16pin 74HC595 74HC595 1 13 15 Q0 2 3 1 Q1 3 4 2 Q2 4 10 3 Q3 5 6 4 Q4 6 11 5 Q5 7 15 6 Q6 8 16 7 Q7 点阵COL 点阵16pin 74HC595 74HC595 1 5 15 Q0 2 2 1 Q1 3 7 2 Q2 4 1 3 Q3 5 12 4 Q4 6 8 5 Q5 7 14 6 Q6 8 9 7 Q7 程序 //Pin 连接到 74HC595的ST_CP int latchPin = 8; //Pin 连接到 74HC595的SH_CP int clockPin = 12; //Pin 连接到 74HC595的DS int dataPin = 11; //设定时间 unsigned long time; //掩盖行定义 byte masks[8]={ B01111111,B10111111,B11011111,B11101111,B11110111,B11111011,B11111101,B11111110}; //笑脸横向移动定义 byte rows[4][8]={ { B00111100,B01000010,B10100101,B10000001,B10100101,B10011001,B01000010,B00111100 } , { B00011110,B00100001,B11010010,B11000000,B11010100,B11001100,B00100001,B00011110 } , { B00001111,B10010000,B11101001,B01100000,B01101010,B01100110,B10010000,B00001111 } , { B10000111,B01001000,B11110100,B00110000,B00110101,B00110011,B01001000,B10000111 } }; void setup() { //波特率为9600，用于调试 Serial.begin(9600); //设置 latchpin 为 output pinMode(latchPin, OUTPUT); } void loop() { //笑脸横向移动 for(int j=0;j<4;j++) { unsigned long startTime = millis(); for (unsigned long elapsed=0; elapsed < 1000; elapsed = millis() - startTime) {//持续显示600ms for(int i=0;i<8;i++) { digitalWrite(latchPin, 0); shiftOut(dataPin, clockPin, masks[i]); //mask(col) shiftOut(dataPin, clockPin, rows[j][i]); //row digitalWrite(latchPin, 1); } } //time=0; } } void shiftOut(int myDataPin, int myClockPin, byte myDataOut) { // This shifts 8 bits out MSB first, //on the rising edge of the clock, //clock idles low //internal function setup int i=0; int pinState; pinMode(myClockPin, OUTPUT); pinMode(myDataPin, OUTPUT); //clear everything out just in case to //prepare shift register for bit shifting digitalWrite(myDataPin, 0); digitalWrite(myClockPin, 0); //for each bit in the byte myDataOut&#239;&#191;&#189; //NOTICE THAT WE ARE COUNTING DOWN in our for loop //This means that %00000001 or "1" will go through such //that it will be pin Q0 that lights. for (i=7; i>=0; i--) { digitalWrite(myClockPin, 0); //if the value passed to myDataOut and a bitmask result // true then... so if we are at i=6 and our value is // %11010100 it would the code compares it to %01000000 // and proceeds to set pinState to 1. if ( myDataOut & (1<<i) ) { pinState= 1; } else { pinState= 0; } //Sets the pin to HIGH or LOW depending on pinState digitalWrite(myDataPin, pinState); //register shifts bits on upstroke of clock pin digitalWrite(myClockPin, 1); //zero the data pin after shift to prevent bleed through digitalWrite(myDataPin, 0); } //stop shifting digitalWrite(myClockPin, 0); } 在程序中定义byte rows[4][8]的四个横向移动动作 调试 步骤一：把代码复制到IDE中，编译 步骤二：电路连接如下图： 为了更好的保护电路，可以在其中一个74HC595芯片连接8*8点阵之间的八条线中各加一个220欧姆电阻，本例中没有加入电阻所以LED特别亮，如果点阵的质量不好的话很容易坏掉。 步骤三：运行代码 结果 8*8点阵LED上面的笑脸会横向移动显示 视频 http://v.youku.com/v_show/id_XNjg2MDQ5ODQ0.html